1/x-5=5/x^2+2x-35

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Solution for 1/x-5=5/x^2+2x-35 equation: 



1/x-5=5/x^2+2x-35

We move all terms to the left:

1/x-5-(5/x^2+2x-35)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2+2x-35)!=0

x∈R



We get rid of parentheses

1/x-5/x^2-2x+35-5=0

We calculate fractions

We do not support expression: x^3

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